According to Moseley-s law the frequency -v- of k- line and the atomic number z of the element have the relation A B are constants

The correct option is B √(v)/Z A=B Moseley's law of k alpha nbsp; (K_α) line is √(f)=K_1(Z K_2) where nbsp; f is frequencyZ is atomic num ...

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Standard XII

Physics

Moseley's Law

According to ...

Question

According to Moseley’s law the frequency $^{'} v^{'}$ of $k_{α}$ line and the atomic number (z) of the element have the relation (A & B are constants)

\frac{v}{Z - A} = B

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\frac{\sqrt{v}}{Z - A} = B

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v (Z - A) = B

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v (Z - A)^{2} = B

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Solution

The correct option is B $\frac{\sqrt{v}}{Z - A} = B$
Moseley's law of k-alpha $(K_{α})$ line is
$\sqrt{f} = K_{1} (Z - K_{2})$
where $f$ is frequency
Z is atomic number
$K_{1} a n d K_{2}$ are constants.
so, $\frac{\sqrt{f}}{(Z - K_{2})} = K_{1}$
or $\frac{\sqrt{ν}}{(Z - A)} = B$
replacing $f b y ν a n d k_{1}, k_{2} b y A, B$ respectively.

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According to Moseley’s law the frequency ′v′ of kα line and the atomic number (z) of the element have the relation (A & B are constants)

The correct option is B √vZ−A=BMoseley's law of k-alpha (Kα) line is√f=K1(Z−K2)where f is frequencyZ is atomic numberK1and K2 are constants.so,√f(Z−K2)=K1or √ν(Z−A)=Breplacing f by ν and k1, k2 by A,B respectively.

According to Moseley’s law the frequency $^{'} v^{'}$ of $k_{α}$ line and the atomic number (z) of the element have the relation (A & B are constants)