Question

According to the CRC's, the melting point of cadmium bromide is ${868}^{\circ }C$. Which of the following equations best describes what occurs when cadmium bromide is heated to ${868}^{\circ }C$?

• A. $CdBr\left(s\right)\to CdBr\left(l\right)$
• B. $CdB{r}_2\left(s\right)\to CdB{r}_2\left(l\right)$
• C. $CdB{r}_2\left(s\right)\to Cd\left(s\right)+B{r}_2\left(g\right)$
• D. $CdB{r}_2\left(s\right)\to C{d}^{2+}\left(aq\right)+2B{r}^{-}\left(aq\right)$

Answer 1

The correct option is B $CdB{r}_2\left(s\right)\to CdB{r}_2\left(l\right)$

Melting of a pure substance is defined as the phase change that happens from a solid phase to the liquid phase. The temperature at which melting happens is called the melting point. Here the melting point of cadmium bromine is ${868}^{o}c$.So at ${868}^{o}c$, there will be a phase change from solid to liquid.