Question

According to the CRC's the melting point of cadmium bromide is ${868}^{\circ }C$. Which of the following equations best describes what occurs when cadmium is heated to ${868}^{\circ }C$?

• A. $CdBr\left(s\right)\to CdBr\left(l\right)$
• B. $CdB{r}_2\left(s\right)\to CdB{r}_2\left(l\right)$
• C. $CdB{r}_2\left(s\right)\to Cd\left(s\right)+B{r}_2\left(g\right)$
• D. $CdB{r}_2\left(s\right)\to C{d}^{2+}\left(aq\right)+2B{r}^{-}\left(aq\right)$

Answer 1

Answer: (B)

$CdB{r}_2\left(s\right)\to CdB{r}_2\left(l\right)$

$\begin{array}{c}\text{At melting point, when a substance, currently in its solid state is}\\ \text{heated, it gets converted into its liquid state.}\\ \text{Thus,}[{CdBr}_2\text{(s)}\frac{\Delta }{{868}^{\circ }C}\cdot {CdBr}_2(l\left)\right]\end{array}$