Question

According to the Hardy-Weinberg’s equation $p^2+q^2+2pq$ should be equal to

• A. \N
• B. 1
• C. 2
• D. 3

Answer 1

The correct option is B 1

HARDY-WEINBERG PRINCIPLE:
This principle says that allele frequencies in a population are stable and is constant from generation to generation. The gene pool (total genes and their alleles in a population) remains a constant. This is called genetic equilibrium. Sum total of all the allelic frequencies is 1. Individual frequencies, for example, can be named p, q, etc. In a diploid, p and q represent the frequency of allele A and allele a. The frequency of AA individuals in a population is simply $p^2$. This is simply stated in another ways, i.e., the probability that an allele A with a frequency of p appear on both the chromosomes of a diploid individual is simply the product of the probabilities, i.e., $p^2$. Similarly, of aa is $q^2$, of Aa $2pq$. Hence, $p^2+2pq+q^2=1$.