CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
Question

According to the modified Ampere's circuital law (iD= displacement current)

A
Bdl=μ0(iC+ε0dϕEdt)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
Bdl=μ0 ε0dϕEdt
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Bdl=μ0 iC
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Bdl=μ0(iC dϕEdt+iD)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A Bdl=μ0(iC+ε0dϕEdt)
According to the modified Ampere's circuital law,

Bdl=μ0(iC+iD)=μ0(iC+ε0dϕEdt)

Where,

B the magnetic induction at any point on the path.

dl is the length element of the path,

ic is the total conduction current through a surface enclosed by the closed path.

Id=ε0dϕdt the fictitious displacement current arising from the changing electric flux ϕe.

Hence, option (A) is correct.

flag
Suggest Corrections
thumbs-up
0
BNAT
mid-banner-image