Question

According to the VB thoery the bonds formed in methane due to overlapping are:

• A. $1\sigma s-s$, $3\sigma s-p$
• B. $1\sigma s-p$, $3\sigma s-s$
• C. $2\sigma s-s$, $2\sigma s-p$
• D. $4\sigma s{p}^3-s$

Answer 1

Answer: (A)

$1\sigma s-s$, $3\sigma s-p$

According to VBT

The mixing of the one s-orbital and three p orbital of the same energy to form four orbital of equal energy to form four orbital of equal in all respect and tetrahedrally arranged is known as

Geometry:

$s{p}^3$ hybridised orbital repel each other and they are directed to four corners of a regular tetrahedron.

Angle between them is ${109.5}^0$and geometry of the molecule is tetrahedron.

This type of hybridisation is also known as tetrahedral hybridisation .

The$s{p}^2$ hybridisation is shown pictorially in the given fig .

So the methyl molecule have one s and three p orbital are present .