Question

According to VBT any covalent bond will be formed by overlapping of valence atomic orbitals of bonded atoms provided atomic orbitals must be half–filled and electrons be in opposite spin. According to type of overlapping covalent bonds can be classified as: (a) $\sigma$ bond (b) $\pi$ bond (c) $\delta$ bond. If $F_2{C}_1=C_2$ part of $F_2{C}_1=C_2=C_3=C_4{F}_2$ lies in $yz$–plane then incorrect statement is:

• A. Nodal plane of $\pi$ bond between $C_1$ and $C_2$ lies in $yz⎯$plane, formed by sideways overlapping of $p_x$ orbitals
• B. Nodal plane of $\pi$ bond between $C_2$ and $C_3$ lies in $xz⎯$plane, formed by sideways overlapping of $p_y$ orbitals
• C. Nodal plane of $\pi$ bond between $C_3$ and $C_4$ lies in $yz⎯$plane, formed by sideways overlapping of $p_y$ orbitals
• D. Nodal plane of $\pi$ bond between $C_2$ and $C_3$ lies in $xy⎯$plane, formed by sideways overlapping of $p_x$ orbitals

Answer 1

Answer: (C), (D)

Nodal plane of $\pi$ bond between $C_2$ and $C_3$ lies in $xy⎯$plane, formed by sideways overlapping of $p_x$ orbitals

Nodal plane of $\pi$ bond between $C_1$ and $C_2$ lies in $yz⎯$plane, formed by sideways overlapping of $p_x$ orbitals.

Nodal plane of $\pi$ bond between $C_2$ and $C_3$ lies in $xz⎯$plane, formed by sideways overlapping of $p_y$ orbitals.

Nodal plane of $\pi$ bond between $C_3$ and $C_4$ lies in $yz⎯$plane, formed by sideways overlapping of $p_x$ orbitals.

Hence, option (c) and (d) statements are incorrect.