According to VSEPR theory, the most probable shape of the molecule having $4$ electron pairs in the outer shell of the central atom is:

linear

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tetrahedral

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pyramidal

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octahedral

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Solution

The correct option is B tetrahedral
Most probable shape of molecule having $4$ bond pairs with no lone pairs is regular tetrahedron (tetrahedral) Ex:- $C H_{4}, S i F_{4}$

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V S E P R

A B_{3}

I F_{7}

A B_{3}

A

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