Question

According to VSEPR theory predict the geometry and shape of I₃⁺ion.

Answer 1

VSEPR (valence shell electron pair repulsion )theory is used to predict the geometry and shape of the molecule based on a number of electron pairs surrounding the central metal atom or ion.

The formula for determining the hybridization is:

=1/2{No of valence electron in central atom+ Monovalent atom attached to central metal atom+anionic charge-cationic charge}

Applying the equation to the ${{\mathrm{I}}_3}^{+}\mathrm{ion}$,

$1/2[7+2-1+0]=4=$ ${\mathrm{sp}}^3$ where iodine has seven valence electrons.

The valency of iodine is one since it belongs to group $17$ of the periodic table and needs one electron to complete octet configuration.

The central atom has 6 electrons because of the one positive charge.

The electron pair which doesn't take part in bond formation is called the lone pair.

lone pair will be an upside, thus making a bent shape.