(i) It is due to greater extent of association in
1∘ amines because the extent of H-bonding in
1∘ amines is more than in case
3∘ amines. As in
1∘ amines N-atom is attached to two H-atoms while in
3∘ amines there is no H-atom linked to N-atom.
(ii) Aniline is a Lewis base while
AlCl3 is a Lewis acid. They combine with each other to form salt.
Due to presence of a positive charge on N-atom in the salt, the group
−+NH2AlCl−3 acts as a strong electron withdrawing group. As a result it reduces electron density in the benzene ring and hence aniline does not undergo Friedel Craft's reaction.
(iii)
(CH3)2NH is more basic than
(CH3)3N due to greater stability of conjugate acid
(CH3)2+NH2 over
(CH3)3+NH due to greater extent of H-bonding.