Question

Acetaldehyde and excess ethyl alchohol reacts in presence of dry HCl gas. The product obtained is :

• A. $$C{H}_{3}C{H}_{2}C{H}_{2}OH$$
• B. $$C{H}_3-CH\left(OH\right)-C{H}_3$$
• C. $$C{H}_3-CH\left(OH\right)-C_2{H}_5$$
• D. $$C{H}_{3}CH(O{C}_2{H}_5{)}_2$$

Answer 1

The correct option is D $$C{H}_{3}CH(O{C}_2{H}_5{)}_2$$

Aldehydes react with one equivalent of monohydric alcohol in the presence of dry hydrogen chloride to yield alkoxyalcohol intermediate, known as $\underset{–}{\text{hemiacetals,}}$ which further reacts with one more molecule of alcohol to give a gem-dialkoxy compound known as $\underset{–}{\text{acetal.}}$

So, the correct option is (d).