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Acetic acid d...

Question

Acetic acid dimerises in vapour phase at $437 K$ as $2 C H_{3} C O O H (g) ⇌ {(C H_{3} C O O H)}_{2} (g)$ . A mass of $0.0519 g$ of acetic acid was found to have $764.3 m m$ pressure at $437 K$ in a container of $21.45 {c m}^{3}$ . Calculate degree of dimerisation for acetic acid dimerisation.

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Solution

61%, and equilibrium constant $(K_{c})$ and $(K_{p})$ $2.3 \times 10^{3} l i t r e {m o l}^{- 1}, 64.1 {a t m}^{- 1}$

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Similar questions

Acetic acid undergoes dimerisation, when dissolved in benzene (as shown in figure)
Molecular mass of acetic acid is found to be

120

Which among the following relation is correct?

α

= degree of association,

d

= observed vapour density,

D

= Theoretical vapour density).

C H_{3} C O O H

is added in 250 g benzene. Acetic acid dimerises in benzene due to hydrogen bond.

K_{b}

of benzene is 2 K

k g m o l^{- 1}

. The boiling point has increased by 6.4 K. % dimerisation of acetic acid is :

Q. The freezing point of

0.02 m o l

fraction solution of acetic acid

(A)

(B)

277.4 K

. Acetic acid exists partly as a dimer

2 A = A_{2}

. Calculate equilibrium constant for the dimerisation. Freezing point of benzene is

278.4 K

and its heat of fusion

Δ H_{f}

10.042 k J m o l^{- 1}

Q. The freezing point of

0.02

mole fraction of acetic acid in benzene is

277.4

K. Acetic acid exists partly as dimer. Calculate the equilibrium constant for dimerisation. Freezing point of benzene is

278.4

K and heat of fusion of benzene is

10.042

^{- 1}

.

Q. The freezing point of 0.02 mol fraction solution of acetic acid

(A)

(B)

is 277.4 K. Acetic acid exists partly as a dimer

2 A ⇌ A_{2.}

Calculate the equilibrium constant for the dimerisation? The freezing point of benzene is 278.4 K and its heat of fusion is

10.042 K J m o l^{- 1} .

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