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Question

Acetic acid forms dimer in vapour phase. The dimer is held together by two hydrogen bonds with a total strength of 66.5 kJ per mole of dimer. If at 25oC, the equilibrium constant for the dimerization is 1.3×103. ΔSo for the reaction 2CH3COOH(CH3COOH)2 will be (log1.3=0.1139) :

A
0.163 kJ
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B
0.232 kJ
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C
0.342 kJ
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D
0.456 kJ
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Solution

The correct option is A 0.163 kJ
2CH3COOH(g)(CH3COOH)2(g)

ΔGo=2.303RTlogK

ΔGo=2.303×8.314×298×log(1.3×103)=17767.69J=17.77kJ

Again,
ΔGo=ΔHoTΔSo

17.77=66.5298×ΔSo

ΔSo=(66.5+17.77)298

ΔSo=48.73298=0.163kJ

Therefore, ΔSo=0.163kJ

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