Acetic anhydride + diethyl ether in presence of anhydrous $A l C l_{3}$ gives product

C H_{3} C O O C H_{3}

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C H_{3} C H_{2} C O O C H_{3}

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C H_{3} C O O C_{2} H_{5}

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C H_{3} C H_{2} C O O H

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Solution

The correct option is D $C H_{3} C O O C_{2} H_{5}$
Acetic anhydride + diethyl ether in presence of anhydrous $A l C l_{3}$ gives product ethyl acetate.
$(C H_{3} C O)_{2} O + (C_{2} H_{5})_{2} O A l C l_{3} - -- \to 2 C H_{3} C O O C_{2} H_{5}$

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gives:

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Toluene on heating with succinic anhydride in the presence of anhydrous $A l C l_{3}$ followed by reduction with Zn - Hg/Con. HCl gives a product which on heating with thionylchloride followed by heating with anhydrous $A I C I_{3}$ in $C S_{2}$ gives major product (A), so, the product (A) is:

Toluene on heating with succinic anhydride in the presence of anhydrous followed by reduction with Zn - Hg/Con. HCl gives a product which on heating with thionyl chloride followed by heating with anhydrous $A l C l_{3}$ in $C S_{2}$ gives major product (A), so, the product (A) is:

Q. Acetic anhydride on treatment with diethyl ether forms:

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Acetic anhydride + diethyl ether in presence of anhydrous AlCl3 gives product

The correct option is D CH3COOC2H5Acetic anhydride + diethyl ether in presence of anhydrous AlCl3 gives product ethyl acetate.(CH3CO)2O+(C2H5)2OAlCl3−−−→2CH3COOC2H5

Acetic anhydride + diethyl ether in presence of anhydrous $A l C l_{3}$ gives product

The correct option is D $C H_{3} C O O C_{2} H_{5}$
Acetic anhydride + diethyl ether in presence of anhydrous $A l C l_{3}$ gives product ethyl acetate.
$(C H_{3} C O)_{2} O + (C_{2} H_{5})_{2} O A l C l_{3} - -- \to 2 C H_{3} C O O C_{2} H_{5}$