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Question

Acetone and carbon disulphide form binary liquid solution showing positive deviation from Raoult's law. The normal boiling point (Tb) of pure acetone is less than that of pure CS2. Pick out the incorrect statements among the following.

A
The boiling temperature of the mixture is always less than the boiling temperature of acetone.
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B
The boiling temperature of Azeotropic mixture is always less than the boiling temperature of pure CS2.
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C
When a small amount of CS2(less volatile component) is added to an excess of acetone boiling point of resulting mixture increases.
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D
A mixture of CS2 and CH3COCH3 can be completely separated by simple fractional distillation.
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Solution

The correct options are
A The boiling temperature of the mixture is always less than the boiling temperature of acetone.
C When a small amount of CS2(less volatile component) is added to an excess of acetone boiling point of resulting mixture increases.
D A mixture of CS2 and CH3COCH3 can be completely separated by simple fractional distillation.
The boiling temperature of the mixture is more than the boiling temperature of acetone when the appreciable amount of carbon disulfide is added. This is because less volatile carbon disulphide is added to more volatile acetone.
When a small amount of CS2 (less volatile component) is added to an excess of acetone boiling point of the resulting mixture will not increase. This is because the total vapour pressure is greater than that predicted by Raoult's law due to positive deviation.
A mixture of CS2 and CH3COCH3 cannot be completely separated by simple fractional distillation as an azeotropic mixture or constant boiling mixture is formed.

Hence, the correct options are A, C and D

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