Acetone and carbon disulphide form binary liquid solution showing positive deviation from Raoult's law. The normal boiling point $(T_{b})$ of pure acetone is less than that of pure $C S_{2}$ . Pick out the incorrect statements among the following.

The boiling temperature of the mixture is always less than the boiling temperature of acetone.

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The boiling temperature of Azeotropic mixture is always less than the boiling temperature of pure

C S_{2}

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When a small amount of

C S_{2} (l e s s v o l a t i l e c o m p o n e n t)

is added to an excess of acetone boiling point of resulting mixture increases.

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A mixture of

C S_{2}

and

C H_{3} C O C H_{3}

can be completely separated by simple fractional distillation.

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Solution

The correct options are
A The boiling temperature of the mixture is always less than the boiling temperature of acetone.
C When a small amount of $C S_{2} (l e s s v o l a t i l e c o m p o n e n t)$ is added to an excess of acetone boiling point of resulting mixture increases.
D A mixture of $C S_{2}$ and $C H_{3} C O C H_{3}$ can be completely separated by simple fractional distillation.
The boiling temperature of the mixture is more than the boiling temperature of acetone when the appreciable amount of carbon disulfide is added. This is because less volatile carbon disulphide is added to more volatile acetone.
When a small amount of $C S_{2}$ (less volatile component) is added to an excess of acetone boiling point of the resulting mixture will not increase. This is because the total vapour pressure is greater than that predicted by Raoult's law due to positive deviation.
A mixture of $C S_{2}$ and $C H_{3} C O C H_{3}$ cannot be completely separated by simple fractional distillation as an azeotropic mixture or constant boiling mixture is formed.

Hence, the correct options are $A$ , $C$ and $D$

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Similar questions

Question 25
On the basis of information given below mark the correct option. Information On adding acetone to methanol some of the hydrogen bonds between methanol molecules break.
(a) At specific composition methanol-acetone mixture will form minimum boiling azeotrope and will show positive deviation from Raoult's law
(b) At specific composition methanol-acetone mixture will form maximum boiling azeotrope and will show positive deviation from Raoult's law
(c) At specific composition methanol-acetone mixture will form minimum boiling azeotrope and will show negative deviation from Raoult's law
(d) At specific composition methanol-acetone mixture will form maximum boiling azeotrope and will show negative deviation from Raoult's law

Q. Assertion:

A mixture of acetone and methanol can be separated by fractional distillation

Reason:

The difference between their boiling point is very less

Q. Binary liquid mixtures which exhibit positive deviations from Raoult's law boil at temperature ______ than the expected boiling point:

Q. A solution made up of mixing two liquids A and B forms an azeotropic mixture at a given composition. Given that pure liquid A boils at lower temperature than pure liquid B, then on fractional distillation of the azeotropic mixture:

Q. Assertion :Benzene (boiling point

353 K

) and methanol (boiling point

338 K

) are separated by simple distillation. Reason: Fractional distillation is used to separate two liquids from their mixture when their boiling points differ by

25 K

or less.

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Acetone and carbon disulphide form binary liquid solution showing positive deviation from Raoult's law. The normal boiling point (Tb) of pure acetone is less than that of pure CS2. Pick out the incorrect statements among the following.

Acetone and carbon disulphide form binary liquid solution showing positive deviation from Raoult's law. The normal boiling point $(T_{b})$ of pure acetone is less than that of pure $C S_{2}$ . Pick out the incorrect statements among the following.