Acetyl bromide reacts with excess of $C H_{3} M g I$ followed by treatment with a saturated solution of $N H_{4} C l$ gives:

acetone

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acetamide

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2-methyl-2-propanol

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acetyl iodide

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Solution

The correct option is D 2-methyl-2-propanol

Acetyl bromide reacts with excess of $C H_{3} M g I$ followed by treatment with a saturated solution of $N H_{4} C l$ gives tertiary alcohol which in the given optionis : 2-methyl-2-propanol.

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Similar questions

C H_{3} M g I

N H_{4} C l

Which among the following compounds on reaction with methyl magnesium bromide followed by hydrolysis with water will give 2-methyl-2-propanol?

C_{6} H_{5} C O O C_{2} H_{5} + C H_{3} M g B r (e x c e s s) D i e t h y l e t h e r ⟶ H_{3} O^{+} ⟶

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