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Question

Acetyl bromide reacts with excess of CH3MgI followed by treatment with a saturated solution of NH4C1 gives:

A
acetone
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B
acetamide
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C
2-methyl-2-propanol
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D
acetyl iodide
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Solution

The correct option is C 2-methyl-2-propanol
Acetyl bromide reacts with excess of
CH3MgI followed by
treatment with a saturated solution of
NH4Cl gives 2-methyl-2-propanol.
379151_41786_ans_83b3bd1723854ab4b0a84e8d30fbd26d.png

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