Acetylene can be obtained by the reaction:

H C O O K E l e c t r o l y s i s - ------ \to

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C H I_{3} + A g Δ - \to

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C H_{3} C H_{2} O H C o n c . H_{2} S O_{4} - ------- \to 443 K

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B e_{2} C + H_{2} O \to

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Solution

The correct option is B $C H I_{3} + A g Δ - \to$
Iodoform and Ag undergo dehalogenation reaction to produce acetylene.
(a) $H C O O K + H_{2} O Δ - \to H_{2} + C O_{2} + K O H$
(b) $2 C H I_{3} i o d o f o r m + 6 A g s i l v e r Δ - \to C H \equiv C H + 6 A g I a c e t y l e n e$
(c) $C H_{3} C H_{2} O H C o n c . H_{2} S O_{4} - ------- \to 443 K C H_{2} = C H_{2} e t h y l e n e + H_{2} O$
(d) $B e_{2} C + 2 H_{2} O \to C H_{4} + 2 B e O m e t h a n e$

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Similar questions

Which is not obtained when metal carbides react with H₂O?

B e_{2} C + H_{2} O \to B e (O H)_{2} + X

C a C_{2} + H_{2} O \to C a (O H)_{2} + Y

X

Y

C H_{3} C H_{2} O H + O_{2} \to

+ H_{2} O

C H_{3} C O O H + C H_{3} C H_{2} O H H_{2} S O_{4} - --- \to

H_{2} O

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