$A c e t y l e n e r e a c t s w i t h 42 % H_{2} S O_{4} c o n t a i n i n g 1 % H g S O_{4} t o g i v e :$

C_{2} H_{5} H S O_{4}

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C H_{3} C H O

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H C H O

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C H_{2} C H_{2}

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Solution

The correct option is B $C H_{3} C H O$
$H C \equiv C H + H_{2} O H_{2} S O_{4} - ---- \to H g S O_{4} [C H_{2} = C H - O H] (V i n y l a l c o h o l) t a u t o m e r i z e s ⇋ C H_{3} - C H O (a c e t a l d e h y d e)$

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A c e t y l e n e r e a c t s w i t h 42 % H_{2} S O_{4} c o n t a i n i n g 1 % H g S O_{4} t o g i v e :

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