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Byju's Answer
Standard XII
Chemistry
pH the Power of H
Acidic charac...
Question
Acidic character increases from HF and HI.
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Solution
The Increasing order of Acidity here will be
H
F
<
H
C
l
<
H
B
r
<
H
I
This is because Acidity is actually nothing but the easiness with which
H
+
ions are released in solution
Here in HI, Iodine has the largest size, thus weakest bond with Hydrogen and hence largest acidity.
The size of the anions increases down the group and hence the order is
H
F
<
H
C
l
<
H
B
r
<
H
I
.
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Similar questions
Q.
Answer the following question:
Arrange the following in the order of property indicated against each set:
a.
H
F
,
H
C
l
,
H
B
r
,
H
I
- increasing bond dissociation enthalpy
b.
H
2
O
,
H
2
S
,
H
2
S
e
,
H
2
T
e
- increasing acidic character.
Q.
(a) Account for the following:
(i) Acidic character increase from
H
F
to
H
I
.
(ii) There is large difference between melting and boiling points of oxygen and sulphur.
(iii) Nitrogen does not from pentahalide.
(b) Draw the structures of the following:
(i)
C
l
F
3
(ii)
X
e
F
4
Q.
Arrange the following in order of property indicated for each set.
(i)
H
2
O
,
H
2
S
,
H
2
S
e
,
H
2
T
e
-increasing acidic character
(ii)
H
F
,
H
C
l
,
H
B
r
,
H
I
-decreasing bond enthalpy
Q.
(a)Account for the following:
(i)Acidic character increase from
H
F
to
H
I
.
(ii)There is a large difference between the melting and boiling points of oxygen and sulphur.
(iii) Nitrogen does not form pentahalide.
(b) Draw the structures of the following:
(i)
C
l
F
3
(ii)
X
e
F
4
Q.
Assign reason for the following:
(i)
H
3
P
O
2
is a stronger reducing agent than
H
3
P
O
4
.
(ii) Sulphur shows more tendency for catenation than Oxygen.
(iii) Reducing character increases from
H
F
to
H
I
.
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