Acidic $K_{2} C r_{2} O_{7}$ reacts with $H_{2} S$ to produce

C r^{6 +} i o n s

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C r^{3 +} i o n s

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S O_{2}

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S

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Solution

The correct options are
B $S$
D $C r^{3 +} i o n s$
${C r}_{2} O_{7}^{2 -} + 3 H_{2} S + 8 H^{+} \to 2 {C r}^{+ 3} + 3 S + 7 H_{2} O$
${C r}^{+ 6} \to {C r}^{+ 3}$ (Reduction)
$S^{2 -} \to S^{0}$ (oxidation)

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