Acidified $K_{2} C r_{2} O_{7}$ solution turns green when $N a_{2} S O_{3}$ is added to it . This is due to the formation of :

 AIPMT Priliminary Examination 2011

C r_{2} {(S O_{3})}_{3}

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C r {(S O_{4})}_{3}

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C r S O_{4}

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C r O_{4}^{2 -}

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Solution

The correct option is B $C r {(S O_{4})}_{3}$
Correct option is D
Acidified $K_{2} C r_{2} O_{7}$ solution turns green when $N a_{2} S O_{3}$ is added to it . This is due to the formation of $C r_{2} {(S O_{4})}_{3}$

$K_{2} C r_{2} O_{7} + 3 N a_{2} S O_{3} + 4 H_{2} S O_{4} \to C r_{2} {(S O_{4})}_{3} + K_{2} S O_{4} + 3 N a_{2} S O_{4} + 4 H_{2} O$

Hence option D is correct .

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