Question

Acidified $K_{2}C{r}_2{O}_7$ oxidizes $H_{2}S$ to

• A. $S{O}_2$
• B. $S{O}_3$
• C. $S$
• D. $H_{2}S{O}_4+S$

Answer 1

The correct option is C $S$

$3H_{2}S+C{r}_2{O}_7^{2-}+8H^{+}\to 2C{r}^{3+}+3S+7H_{2}O$