You visited us 1 times! Enjoying our articles? Unlock Full Access!

Tests for Sulphuric Acid

Acidified K...

Question

Acidified $K_{2} C r_{2} O_{7}$ turns green by :

C O_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

S O_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

S O_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

H N O_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $S O_{2}$
Acidified $K_{2} C r_{2} O_{7}$ turns green by $S O_{2}$ .
$P b C r O_{4}$ , a yellow precipitate, is formed. This is chromyl chloride test.

Suggest Corrections

Similar questions

S O_{2}

K_{2} C r_{2} O_{7}

K_{2} C r_{2} O_{7}

C r^{3 +}

S O_{2}

S O_{2}

K_{2} C r_{2} O_{7}

S O_{2}

K_{2} C r_{2} O_{7}

(X)

K_{2} C r_{2} O_{7}

X

Join BYJU'S Learning Program