Question

Acidified $KMn{O}_4$ oxidizes oxalic acid to $C{O}_2$. What is the volume (in $litre$) of ${10}^{-4}MKMn{O}_4$ required to completely oxidize $0.5litre$ of ${10}^{-2}M$ oxalic acid in acid medium?

• A. $125$
• B. $1250$
• C. $200$
• D. $20$

Answer 1

The correct option is D $20$

$2KMn{O}_4+3H_{2}S{O}_4+5\underset{COOH}{\stackrel{COOH}{|}}\to K_{2}S{O}_4+2MnS{O}_4+10C{O}_2+8H_{2}O$
$\frac{M_1{V}_1}{n_1}\left(KMn{O}_4\right)=\frac{M_2{V}_2}{n_2}\left(\underset{COOH}{\stackrel{COOH}{|}}\right)$
$\frac{{10}^{-4}\times V_1}{2}=\frac{{10}^{-2}\times 0.5}{5}$
$V_1=20L$.