Acidified potassium dichromatic on reaction with sulphite is reduced to:

C r O_{2} C l_{2}

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C r O_{4}^{2 -}

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C r^{3 +}

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C r^{2 +}

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Solution

The correct option is C $C r^{3 +}$
The reaction between acidified $K_{2} C r_{2} O_{7}$ and $N a_{2} S O_{3}$ is given by:
$K_{2} C r_{2} O_{7}$ +4 $H_{2} S O_{4}$ + 3 $N a_{2} S O_{3}$ $\to$ $C r_{2} (S O_{4})_{3}) + 3$ $N a_{2} S O_{4}$ + $K_{2} S O_{4} + 4 H_{2} O$
In acidic medium $C r^{6 +}$ is reduced to $C r^{3 +}$ and $K_{2} C r_{2} O_{7}$ acts as oxidising agent.

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