Acidified solution of chromic acid on treatment with $H_{2} O_{2}$ yield:

C r O_{3} + H_{2} O + O_{2}

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C r_{2} O_{3} + H_{2} O + O_{2}

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C r O_{5} + H_{2} O

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H_{2} C r_{2} O_{7} + H_{2} O + O_{2}

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Solution

The correct option is C $C r O_{5} + H_{2} O$
$K_{2} C r_{2} O_{7} + H_{2} S O_{4} \to K_{2} S O_{4} + H_{2} C r_{2} O_{7}$

$H_{2} C r_{2} O_{7} + 4 H_{2} O_{2} \to 2 C r O_{5} + 5 H_{2} O$

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Similar questions

Acidified solution of chromic acid on treatment with $H_{2} O_{2}$ gives blue colour which is due to -

C r O_{5} + H_{2} S O_{4} \to C r_{2} (S O_{4})_{3} + H_{2} O + O_{2}

C r O_{5}

O_{2}

C r O_{5} + H_{2} S O_{4} \to C r_{2} (S O_{4})_{3} + H_{2} O + O_{2}

C r O_{5}

O_{2}

[F e (C N)_{6}]^{4 -}

[F e (C N)_{6}]^{3 -}

[F e (C N)_{6}]^{3 -}

[F e (C N)_{6})]^{4 -}

C r O_{5} + H_{2} S O_{4} \to C r_{2} (S O_{4})_{3} + H_{2} O + O_{2},

O_{2}

C r O_{5}

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