Acids of boron on heating with alcohol in presence of conc. $H_{2} S O_{4}$ gives:

non-volatile esters

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volatile esters

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non-volatile ethers

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volatile ethers

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Solution

The correct option is C volatile esters
Acid of boron forms volatile esters on heating with alcohol in presence of conc. $H_{2} S O_{4}$
$B (O H)_{3} + 3 R O H ⟶ B (O R)_{3} + 3 H_{2} O$

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