Acidulated water is electrolysed by 1A current for 16 minutes and 5 seconds using inert electrodes. The volume of gases liberated at STP will be :

224 ml

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112 ml

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168 ml

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336 ml

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Solution

The correct option is C
168 ml

$C a t h o d e : 2 H_{2} O + 2 e^{-} \to H_{2 (g)} + 2 O H_{(a q)}^{-} A n o d e : H_{2} O \to 2 H_{(a q)}^{+} + \frac{1}{2} O_{2 (g)} + 2 e^{-}$
$V o l u m e s o f H_{2} = \frac{22400 \times 1 \times 965}{2 \times 96500} = 112 m l; V o l u m e o f O_{2} = 56 m l; T o t a l v o l u m e = 112 + 56 m l$

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Acidulated water is electrolysed by 1A current for 16 minutes and 5 seconds using inert electrodes. The volume of gases liberated at STP will be :

The correct option is C 168 ml Cathode:2H2O+2e−→H2(g)+2OH−(aq)Anode:H2O→2H+(aq)+12O2(g)+2e− Volumes of H2=22400×1×9652×96500=112ml;Volume of O2=56ml;Total volume=112+56ml