Question

Acting as a reducing agent, a piece of metal M weight $16$ grams gives up $2.25\times {10}^{23}$ electrons. What is the equivalent weight of the metal?

• A. $42.83$
• B. $21.33$
• C. $83.32$
• D. $32$

Answer 1

Answer: (A)

$42.83$

The weight of the metal which will give Avogadro Number of electrons will be the equivalent weight of that metal.

Since $2.25\times {10}^{23}$ electrons are liberated by 16 gram of M

Hence $6.022\times {10}^{23}$ electrons will be liberated by $16\times \frac{6.022\times {10}^{23}}{2.25\times {10}^{23}}=42.83$