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Hydrogen Peroxide

Active mass o...

Question

Active mass of 56 g of $N_{2}$ contained in 2 ltr. flask is:

A

16 m o l e . l i t^{- 1}

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B

32 m o l e . l i t^{- 1}

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C

1.00 m o l e . l i t^{- 1}

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D

0.1 m o l e . l i t^{- 1}

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Solution

The correct option is C $1.00 m o l e . l i t^{- 1}$
The expression for the active mass is $Active mass = \frac{number of moles}{volume in litres} = \frac{\frac{m a s s}{molar mass}}{volume in litres}$ .
Substitute values in the above expression.
$Active mass = \frac{\frac{56}{28}}{2} = 1.00 m o l e l i t^{- 1}$ .

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