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Question

Activity of a radioactive element decreased to one third of original activity I0 in 9 years. After further 9 years, its activity will be
  1. I0
  2. 23 I0
  3. I09
  4. I06


Solution

The correct option is C I09

Activity dNdt=λNoeλt
I(t)=Ioeλt

After 9 years:
13=e9λ


After further 9 years
t=18 years
I(18)=Ioe18λ
I(18)Io=(e9λ)2=(1/3)2
I(18)=Io9​​

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