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Question

Actual length of a rope is 22.5 m but it is wrongly meassured as 21.6 m. Find the percentage error

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Solution

You can apply a simple formula for this...

Percent error = (amount of error)/accepted value

Amount of error=22.5-21.6
=0.9
Accepted value means the original length or actual length ie.22.5
so 0.9/22.5=0.04=
Ie..4%

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