Question

Actual length of a rope is 22.5 m but it is wrongly measured as 21.6 m. Find the percentage error.

Answer 1

Error measured = 22.5 – 21.6 = 0.9 m
So the percentage of error = $\frac{0.9}{22.5}\times 100$%
We get
= $\frac{9}{225}\times 100$
= 4%