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Triangles

AD=5.7cm, BD=...

Question

$A D = 5.7 c m, B D = 9.5 c m, A E = 3.6 c m$ and $E C = 6 c m$

Yes

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Solution

The correct option is A Yes
Given: AD = 5.7 cm, BD = 9.5 cm, AE = 3.6 cm and EC = 6 cm
$\frac{A D}{B D} = \frac{5.7}{9.5} = \frac{3}{5}$
$\frac{A E}{E C} = \frac{3.6}{6} = \frac{3}{5}$
Since, $\frac{A D}{B D} = \frac{A E}{E C} = \frac{3}{5}$
By converse of equal Intercept theorem, $D E ∥ B C$

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Similar questions

∆ A B C

D E ∥ B C

A D = 5.7 cm, D B = 9.5 cm, B D = 4.8 cm and E C = 8 cm .

A B = 11.7 cm, A C = 11.2 cm, B D = 6.5 cm and A E = 4.2 cm .

A B = 10.8 cm, A D = 6.3 cm, A C = 9.6 cm and E C = 4 cm .

A D = 7.2 cm, A E = 6.4 cm, A B = 12 cm and A C = 10 cm .

D and E are points on the sides AB and AC respectively of a $Δ A B C$ . In each of the follwing cases, determine whether DE || BC or not.

(i) AD = 5.7 cm, DB = 9.5 cm, AE = 4.8 cm and EC = 8 cm.

(ii) AB = 11.7 cm, AC = 11.2 cm, BD = 6.5 cm and AE = 4.2 cm.

(iii) AB = 10.8 cm, AD = 6.3 cm, AC = 9.6 cm and EC = 4 cm.

(iv) AD = 7.2 cm, AE = 6.4 cm, AB = 12 cm and AC = 10 cm.

△

A B C, D

E

D E

∥

B C

A B = 12 c m, A D = 8 c m, A E = 12 c m a n d A C = 18 c m

A B = 5.6 c m, A D = 1.4 c m, A C = 7.2 c m a n d A E = 1.8 c m

A B = 10.8 c m, B D = 4.5 c m, A C = 4.8 c m a n d A E = 2.8 c m

A D = 5.7 c m, B D = 9.5 c m, A E = 3.3 c m a n d E C = 5.5 c m .

D E ∥ B C

A D = 3.6 c m, A B = 9 c m

A E = 2.4 c m

E C

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