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Condition for Two Lines to Be Parallel

AD bisects th...

Question

AD bisects the angle A of a $Δ A B C$ and meets BC at D. If BC = K metro, CA = l metro, and AB = m metro, then find the length of DC.

\frac{K l}{m + l}

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\frac{K (m + l)}{l}

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\frac{K m}{m + 1}

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\frac{K (m + 1)}{m}

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Solution

The correct option is A $\frac{K l}{m + l}$
Since we know that bisector of a triangle divides the sides in a ratio equal to that of ratio of sides containing it,
So, $D C = B C \times \frac{A C}{A C + A B} D C = \frac{K l}{m + l}$

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Similar questions

A D

∠ A

Δ A B C

B C

D

B C = K

C A = l

A B = m

D C

A B C

B

B C = 10

100

L_{1}, L_{2}, L_{3}, \dots, L_{100}

A B

A B

101

L_{1} M_{1}, L_{2} M_{2}, \dots, L_{100} M_{100}

B C

M_{1}, M_{2}, M_{3}, \dots M_{100}

A C

L_{1} M_{1}, L_{2} M_{2}, \dots, L_{100} M_{100}

l = log \frac{a^{2}}{b c}

m = log \frac{b^{2}}{c a}

n = log \frac{c^{2}}{a b}

l + m + n

A B | | D C a n d A D | | B C .

a r (A B C D) = L a n d a r (A C E D) = M,

a r (A D C) : a r (D E C)

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