wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

AD is a diameter of a circle and AB is a chord If AD = 34 cm, AB = 30 cm the distance of AB from the centre of the circle is

A
17 cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
15 cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
4 cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
8 cm
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 8 cm
OX is the perpendicular distance from centre O to the chord AB
AX=XB
Now,
AX+XB=AB
2AX=AB
2AX=30
AX=302
AX=15
Again,
AO+OD=AD
2AO=AD
2AO=34
AO=17
AOX is a right angled triangle
AO2=OX2+AX2
172=OX2+152
OX2=172152
OX2=64
OX=8cm

399899_426538_ans.jpg

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Circles and Their Chords - Theorem 4
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon