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Converse of Pythagoras Theorem by Contradiction

AD is a media...

Question

AD is a median of $△$ ABC. E is the mid-point of AD. BE produced meets AD at F. The ratio AF : FC =

1 : 3

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2 : 1

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1 : 2

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None of the above

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Solution

The correct option is C $1 : 3$
Draw DP & BF.
F is mid-point of AP and P is mid-point of FC.
Hence $A F = \frac{1}{3} A C$

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