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Question

AD is an altitude of an isosceles triangles ABC in which AB = AC. Show that
AD bisets BC

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Solution


In ΔBAD and ΔCAD,
ADB=ADC (Each 90 since AD is an altitude)
AB = AC (Given)
AD = AD (Common)
ΔBADΔCAD (By RHS Congruence rule)
BD = CD (By CPCT)
Hence, AD bisects BC.

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