Question

$AD$ is the internal bisector of $\angle A$ of triangle $ABC$ and meets side $BC$ at $D$. If $BD=5cm,BC=7.5cm$ then $AB:AC$ is

• A. $2:1$
• B. $1:2$
• C. $4:5$
• D. $3:5$

Answer 1

The correct option is A $2:1$

$AD$ is bisector of $\angle A$
In $△ABD$ and $△ACD$
$\therefore \frac{AB}{AC}=\frac{BD}{DC}=\frac{5}{7.5-5}$
$=\frac{5}{2.5}=2:1$.