Question

AD is the median of a triangle ABC. Area of $\Delta ADC=15c{m}^2$, then ar$\left(\Delta ABC\right)$ is :

• A. 15 $c{m}^2$
• B. 22.5 $c{m}^2$
• C. 30 $c{m}^2$
• D. 37.5 $c{m}^2$

Answer 1

The correct option is C 30 $c{m}^2$

Median divides the triangle in two triangles of equal area.

$\therefore ar\left(△ABC\right)=2ar\left(△ADC\right)$

$ar\left(△ABC\right)=2\times 15=30{cm}^2$