Question

AD is the perpendicular bisector of BC. Find $\angle ADB.$

• A. ${90}^o$
• B. ${65}^o$
• C. ${55}^o$
• D. ${75}^o$

Answer 1

The correct option is A ${90}^o$

$AD\perp BC$

$\therefore \angle ADB={90}^{\circ }$

Hence option $A$ is correct.