Adam took a surprise test of the students of his class on a topic which was taught in the class two weeks earlier. The test consisted of seven questions out of which students needed to attempt only five questions. Shane, a student of his class attempted five questions and copied these five questions on a notebook so that he could solve these questions at his home, and verify whether he answered these questions correctly or not. Help Shane in verifying the answer to these questions.

What will be the unit digit of $(0! + 1! + 2! + 3!) \times 7 \times 53 \times 99 \times 1236$ ?

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Solution

The correct option is C $0$
$0! + 1! + 2! + 3! = 1 + 1 + 2 + 6 = 10$

So, the unit digit of $(0! + 1! + 2! + 3!) = 0$

If we multiply $10$ with any number, the unit digit will always be $0$ .

Thus, the unit digit of the given number will also be $0$ .

Hence, option $D$ is the correct answer.

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Q. Adam took a surprise test of the students of his class on a topic which was taught in the class two weeks earlier. The test consisted of seven questions out of which students needed to attempt only five questions. Shane, a student of his class attempted five questions and copied these five questions on a notebook so that he could solve these questions at his home, and verify whether he answered these questions correctly or not. Help Shane in verifying the answer to these questions.

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The correct option is C 0 0!+1!+2!+3!=1+1+2+6=10 So, the unit digit of (0!+1!+2!+3!)=0 If we multiply 10 with any number, the unit digit will always be 0 . Thus, the unit digit of the given number will also be 0 . Hence, option D is the correct answer.

The correct option is C $0$
$0! + 1! + 2! + 3! = 1 + 1 + 2 + 6 = 10$

So, the unit digit of $(0! + 1! + 2! + 3!) = 0$

If we multiply $10$ with any number, the unit digit will always be $0$ .

Thus, the unit digit of the given number will also be $0$ .

Hence, option $D$ is the correct answer.