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Add:
2p4−3p3+p2−5p+7,−3p4−7p3−3p2−p−12
2p4−3p3+p2−5p+7,−3p4−7p3−3p2−p−12
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Solution
Given that:2p4−3p3+p2−5p+7&−3p4−7p3−3p2−p−12now add both of them,=(2p4−3p3+p2−5p+7)+(−3p4−7p3−3p2−p−12)
=(2p4+(−3p4))+((−3p3)+(−7p3))+((p2)+(−3p2))+(−5p−p)+(7−12)=−p4−10p3−2p2−6p−5
2p4−3p3+p2−5p+7&−3p4−7p3−3p2−p−12
now add both of them,
=(2p4−3p3+p2−5p+7)+(−3p4−7p3−3p2−p−12)
=(2p4+(−3p4))+((−3p3)+(−7p3))+((p2)+(−3p2))+(−5p−p)+(7−12)
=−p4−10p3−2p2−6p−5
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