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Question

Add 2a+3b+c+d, a+bcd and 3a4b2c2d. Find the value of the final expression if a=2, b=3, c=4, d=5. [3 MARKS]

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Solution

Forming the equation: 1 Mark
Sum: 1 Mark
Value: 1 Mark

We have to find the sum of the expressions
2a+3b+c+d, a+bcd
and 3a4b2c2d.


(2a+3b+c+d)+(a+bcd)+(3a4b2c2d)

2a+3b+c+da+bcd+3a4b2c2d

2aa+3a+3b+b4b+cc2c+dd2d

4a+0×b2c2d

Sum =4a2c2d
As per question ,
a = 2, b = 3, c = 4, d = 5
So, on substituting the values we get,
Sum = 4×22×42×5
=8810
= 10
The value of the expression is 10.


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