Add 2 x2-3 x-1 to the sum of 3 x2-2 x and 3 x-7

nbsp;Sum of 3x2 2x and 3x + 7 = (3x2 2x) + ( 3x +7) = 3x2 2x + 3x + 7 = (3x2 + x nbsp; + 7) Now, required expression = (2x2 3x + 1) + (3x2 + x nb ...

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Byju's Answer

Standard VII

Mathematics

Addition and Subtraction of Algebraic Expressions

Add 2 x2-3 x+...

Question

Add 2x² − 3x + 1 to the sum of 3x² − 2x and 3x + 7.

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Solution

Sum of 3x² - 2x and 3x + 7
= (3x² - 2x) + ( 3x +7)
= 3x² - 2x + 3x + 7
= (3x² + x + 7)
Now, required expression = (2x² - 3x + 1) + (3x² + x + 7)
= 2x² + 3x²- 3x + x + 1 + 7
= 5x² - 2x + 8

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(3 x^{2} - \frac{1}{5} x + \frac{7}{3}) + (- \frac{1}{4} x^{2} + \frac{1}{3} x + \frac{1}{3} x - \frac{1}{6}) + (- 2 x^{2} - \frac{1}{2} x + 5)

Question 5
Which of the following equations has the sum of its roots as 3?
(a) $2 x^{2} - 3 x + 6 = 0$
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Which of the following equations has the sum of its roots as 3?
(a)

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(b)

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(c)

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Add:

2, \frac{2}{3} x - \frac{5}{3} x^{2} + \frac{5}{2} x^{3}, \frac{- 4}{3} + \frac{2 x^{2}}{3} - \frac{x}{2}, \frac{5 x^{3}}{3} + 3 x^{2} + 3 x + \frac{6}{5}

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Add 2x2 − 3x + 1 to the sum of 3x2 − 2x and 3x + 7.

Sum of 3x2 - 2x and 3x + 7 = (3x2 - 2x) + ( 3x +7) = 3x2 - 2x + 3x + 7 = (3x2 + x + 7) Now, required expression = (2x2 - 3x + 1) + (3x2 + x + 7) = 2x2 + 3x2 - 3x + x + 1 + 7 = 5x2 - 2x + 8

Add 2x² − 3x + 1 to the sum of 3x² − 2x and 3x + 7.

Sum of 3x² - 2x and 3x + 7
= (3x² - 2x) + ( 3x +7)
= 3x² - 2x + 3x + 7
= (3x² + x + 7)
Now, required expression = (2x² - 3x + 1) + (3x² + x + 7)
= 2x² + 3x²- 3x + x + 1 + 7
= 5x² - 2x + 8