Add:
3a2b+2ab-3b2,2b2-ab+2a2b,ab-2b2-3a2b.
Given algebraic expressions: 3a2b+2ab-3b2,2b2-ab+2a2b,ab-2b2-3a2b.
Arrange the variables in proper columns and solve them,
3a2b+2ab-3b22a2b-ab+2b2-3a2b+ab-2b2_________________2a2b+2ab-3b2
Hence, sum of the given algebraic expressions is 2a2b+2ab-3b2.
In a medical examination of students of a class, the following blood groups are recorded.
A student is selected at random from the class. The probability that he/she has blood groupB, is