Add3a−2b+5c,2a+5b−7c,−a−b+c
We have, (3a−2b+5c)+(2a+5b−7c)+(−a−b+c)
=3a+2a−a−2b+5b−b+5c−7c+c
=5a−a−3b+5b+6c−7c
=4a+2b−c
Simplify:(a−2b+5c)(a−b)−(a−b−c)(2a+3c)+(6a+b)(2c−3a−5b)
Question 81 (vii)
Add :
3a(2b+5c),3c(2a+2b)