Add : $3 a + 4 b - 2 c$ and $- 6 a - 2 b + 3 c$

Open in App

Solution

add $3 a + 4 b - 2 c$ and $- 6 a - 2 b + 3 c$
$(3 a + 4 b - 2 c) + (- b a - 2 b + 3 c)$
$\Rightarrow (3 a - 6 a) + (4 b - 2 b) + (3 c - 2 c)$
$\Rightarrow - 3 a + 2 b + c$

Suggest Corrections

Similar questions

Simplify:
$(a - 2 b + 5 c) (a - b) - (a - b - c) (2 a + 3 c) + (6 a + b) (2 c - 3 a - 5 b)$

∣ ∣ ∣ ∣ \begin{matrix} a & a + b & a + b + c 2 a & 3 a + 2 b & 4 a + 3 b + 2 c 3 a & 6 a + 3 b & 10 a + 6 b + 3 c \end{matrix} ∣ ∣ ∣ ∣ = a^{3}

Question 81 (vii)

Add :

$3 a (2 b + 5 c), 3 c (2 a + 2 b)$

∣ ∣ ∣ ∣ \begin{matrix} a & a + b & a + b + c 2 a & 3 a + 2 b & 4 a + 3 b + 2 c 3 a & 6 a + 3 b & 10 a + 6 b + 3 c \end{matrix} ∣ ∣ ∣ ∣

Join BYJU'S Learning Program