Add - 6 - 3-3 and 8 - 4-3

The correct option is D 14+7√(3) 6+3√(3)+8+4√(3) #160; =6+8+3√(3)+4√(3) =14+3√(3)+4√(3) =14+√(3)(3+4) =14+√(3)× 7 #160; ...

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Byju's Answer

Standard IX

Mathematics

Operations on Rational and Irrational Numbers

Add : 6 + 3...

Question

Add : $6 + 3 \sqrt{3}$ and $8 + 4 \sqrt{3}$

1 + 7 \sqrt{3}

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8 + 7 \sqrt{3}

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14 + 7 \sqrt{3}

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4 + 7 \sqrt{3}

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Solution

The correct option is D $14 + 7 \sqrt{3}$
$6 + 3 \sqrt{3} + 8 + 4 \sqrt{3}$

$= 6 + 8 + 3 \sqrt{3} + 4 \sqrt{3}$

$= 14 + 3 \sqrt{3} + 4 \sqrt{3}$

$= 14 + \sqrt{3} (3 + 4)$

$= 14 + \sqrt{3} \times 7$

$= 14 + 7 \sqrt{3}$

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Similar questions

Find:

(i) (ii) (iii)

(iv) (v) (vi)

Verify the following :

(i) $\frac{3}{7} \times (\frac{5}{6} + \frac{12}{13}) = (\frac{3}{7} \times \frac{5}{6}) + (\frac{3}{7} \times \frac{12}{13})$
(ii) $\frac{- 15}{4} \times (\frac{3}{7} + \frac{- 12}{5}) = (\frac{- 15}{4} \times \frac{3}{7}) + (\frac{- 15}{4} \times \frac{- 12}{5})$
(iii) $(\frac{- 8}{3} + \frac{- 13}{12}) \times \frac{5}{6} = (\frac{- 8}{3} \times \frac{5}{6}) + (\frac{- 13}{12} \times \frac{5}{6})$
(iv) $\frac{- 16}{7} \times (\frac{- 8}{9} + \frac{- 7}{6}) = (\frac{- 16}{7} \times \frac{- 8}{9}) + (\frac{- 16}{7} \times \frac{- 7}{6})$

Q. Simplify :

\frac{2 \frac{3}{4}}{1 \frac{5}{6}} \div \frac{7}{8} \times (\frac{1}{3} + \frac{1}{4}) + \frac{5}{7} \div \frac{3}{4}

\frac{3}{7}

Q. Find the value of:

(1) 3⁶
(2) 6³
(3) 2⁶
(4) 1⁸
(5) 5⁴
(6) 4³
(7) 10⁵
(8) 10⁷
(9) 7⁴
(10) 8²

Add using number line:

(1) 5 and 3

(2) 6 and 2

(3) (−3) and (+5)

(4) 8 and (−12)

(5) (−7) and 5

(6) 10 and (−14)

(7) (−5) and (−2)

(8) (+6) and (−9)

(9) (−4) and (−1)

(10) 1 and (−5)

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Add : 6+3√3 and 8+4√3

The correct option is D 14+7√36+3√3+8+4√3 =6+8+3√3+4√3=14+3√3+4√3=14+√3(3+4)=14+√3×7 =14+7√3

Add : $6 + 3 \sqrt{3}$ and $8 + 4 \sqrt{3}$

The correct option is D $14 + 7 \sqrt{3}$
$6 + 3 \sqrt{3} + 8 + 4 \sqrt{3}$

$= 6 + 8 + 3 \sqrt{3} + 4 \sqrt{3}$

$= 14 + 3 \sqrt{3} + 4 \sqrt{3}$

$= 14 + \sqrt{3} (3 + 4)$

$= 14 + \sqrt{3} \times 7$

$= 14 + 7 \sqrt{3}$